$4\times 3$

$3\times 4$

$5\times 4$

$3\times 5$

${\cos }^{-1}(-\frac{1}{2})$

${\cos }^{-1}\left(\frac{2}{3}\right)$

${\cos }^{-1}\left(\frac{1}{2}\right)$

${\cos }^{-1}\left(\frac{-2}{3}\right)$

3x-2y+5=0

3x+2y+1=0

3x+2y-1=0

3x+2y+1=0

1-i

1+i

$\pm (1-i)$

$\pm (1+i)$

$-3<x<5$

$-3<x<\frac{5}{2}$

$-3<x<\frac{3}{5}$

$-3<x<\frac{5}{3}$

$(9, 4)$

$(\frac{9}{4}, 0)$

$(4, 0)$

$(\frac{4}{9}, 0)$

26

8

4

00

$\left(1,\sqrt{3}\right)$

$\left(1,-\sqrt{3}\right)$

$\left(-1,\sqrt{3}\right)$

$\left(-1,-\sqrt{3}\right)$

$\frac{2}{3}$

$-\frac{2}{3}$

$\frac{3}{2}$

$\frac{-3}{2}$

1

-1

12

-12

$\frac{12}{25}$

$\frac{23}{25}$

$\frac{24}{25}$

$\frac{13}{25}$

$\frac{56}{33}$

$\frac{-56}{33}$

$\frac{10}{13}$

$\frac{-10}{23}$

$x^2-10x+34=0$

$x^2-5x+3=0$

$x^2-6x+16=0$

$x^2+10x-4=0$

$\frac{3}{8}$

$\frac{8}{3}$

$\frac{9}{2}$

$\frac{1}{8}$

120

130

140

150

1

-1

2

-2

$\frac{\pi }{4}$

$\frac{{\displaystyle \pi }}{{\displaystyle 3}}$

$\frac{{\displaystyle \pi }}{{\displaystyle 2}}$

$\frac{{\displaystyle \pi }}{{\displaystyle 6}}$

${30}^{\circ }$

${60}^{\circ }$

${90}^{\circ }$

${120}^{\circ }$

$1+y^2$

$2(1+y^2)$

$2y(1+y^2)$

$1+x^2$

$\frac{1}{Inx}$

$\frac{-1}{Inx}$

$\frac{1}{x}$

$Inx$

$\frac{3}{20}$

$\frac{5}{20}$

$\frac{8}{20}$

$\frac{9}{20}$

2,3

$\left[2,3\right]$

$IR-\left[2,3\right]$

$IR-(2,3)$

-2

2

4

$\left|2x-3\right|<3$

$\left|2x-5\right|<3$

$\left|x-3\right|<3$h xmlns="http://www.w3.org/1998/Math/MathML">x-3<3

$\left|x\right|<3$

(4,-4)

(-4,4)

(4,4)

(-4,-4)

$\frac{\mathrm{\pi }}{6}$

$\frac{\mathrm{\pi }}{3}$

$\frac{\mathrm{\pi }}{4}$

$\frac{2\mathrm{\pi }}{3}$

1/6

1/36

5/36

7/36

2 sec

3 sec

4 sec

5 sec

$\frac{1}{\sqrt{5}}$

$\frac{9}{\sqrt{5}}$

$3\sqrt{3}$

1520

1680

1679

15120

1

2

কোনোটিই নয়

$\frac{{10}^{-x}}{{\log }_{10}e}$

$\frac{{\displaystyle {10}^x}}{{\displaystyle {\log }_{10}e}}$

${10}^x{\log }_{e}10$

$\frac{{10}^x}{10}$

4

8

12

-8

$\sqrt{21}$

$\sqrt{19}$

$\sqrt{15}$

$\sqrt{13}$

$\frac{n^2-1}{12}$

$\frac{n+1}{2}$

$\frac{n^2+1}{12}$

$\frac{n(n+1)}{2}$