y -3 = x + 1

y + 1 = x-3

Y + 3 = x-1

y-1 =x -3

2

1

-2

-1

(4,2)

(-2,-4)

(2,4)

(-4,-2)

-180

160

-160

420

$2+\sqrt{2}$

$2-\sqrt{3}$

$2 +\sqrt{3}$

$3+\sqrt{2}$

$16.63°$

$20.63°$

$88.34°$

$11.54°$

$e^{{\tan }^{-1}}x$

$e^{{\tan }^{-1}}x(1+x^2)$

$\frac{e^{{\tan }^{-1}x}}{1+x^2}$

$\frac{1}{1+x^2}$

8

12

6

-12

1

$\frac{\mathrm{\pi }}{4}$

$\frac{\mathrm{\pi }}{2}$

3p

2p

$2\sqrt{3p}$

$3\sqrt{2}p$

1/2

2

1

9

8

7

6

720

360

180

5040

$\frac{4}{15}$

$\frac{6}{15}$

$\frac{1}{5}$

$\frac{1}{3}$

$x{e}^x$

$\frac{x{e}^x}{x+1}$

$\frac{e^x}{x+1}$

$e^{x}1n(x+1)$

x<1

x <6 এবং x>1

x>6

x>2

24

32

16

8

$4{\cos }^{3}A -3\cos A$

$4{\sin }^{3}A - 3\sin A$

$3 \cos A - 4{\cos }^3$

$3\sin A - 4{\sin }^{3}A$

$\frac{y}{4}\tan x$

$\frac{y}{2}\tan x$

$\frac{y^2}{2}$

$\frac{y}{2} {\tan }^{2}x$

$4\mathrm{\pi }$

$\mathrm{\pi }$

$2\mathrm{\pi }$

$\mathrm{\pi }/2$

$\frac{1}{\sqrt{x}(\sqrt{x}+1{)}^2}$

$\frac{1}{\sqrt{x}(\sqrt{x}+1{)}^2}$

$\frac{1}{\sqrt{x}(\sqrt{x}+1{)}^2}$

$\frac{-1}{\sqrt{x(\sqrt{x}-1{)}^2}}$

2(e +1)

2 (1-e)

2(e-1)

(e+1)

7

4

5

11

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{1}{2}$

$\frac{1}{8}$

1600

2025

2500

1225